/*
 * $XConsortium: CmapAlloc.c,v 1.7 92/11/24 14:15:51 rws Exp $
 * 
 * Copyright 1989 by the Massachusetts Institute of Technology
 *
 * Permission to use, copy, modify, and distribute this software and its
 * documentation for any purpose and without fee is hereby granted, provided 
 * that the above copyright notice appear in all copies and that both that 
 * copyright notice and this permission notice appear in supporting 
 * documentation, and that the name of M.I.T. not be used in advertising
 * or publicity pertaining to distribution of the software without specific, 
 * written prior permission. M.I.T. makes no representations about the 
 * suitability of this software for any purpose.  It is provided "as is"
 * without express or implied warranty.
 *
 * M.I.T. DISCLAIMS ALL WARRANTIES WITH REGARD TO THIS SOFTWARE, INCLUDING ALL
 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS, IN NO EVENT SHALL M.I.T.
 * BE LIABLE FOR ANY SPECIAL, INDIRECT OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES
 * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN ACTION
 * OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF OR IN
 * CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE.
 *
 * Author:  Donna Converse, MIT X Consortium
 */


#ifdef VMS
#   include <X11_DIRECTORY/Xlib.h>
#   include <X11_DIRECTORY/Xatom.h>
#   include <X11_DIRECTORY/Xutil.h>
#else
#   include <X11/Xlib.h>
#   include <X11/Xatom.h>
#   include <X11/Xutil.h>
#endif

#include <stdio.h>

#define lowbit(x) ((x) & (~(x) + 1))

static int default_allocation();
static void best_allocation();
static void gray_allocation();
static int icbrt();
static int icbrt_with_bits();
static int icbrt_with_guess();

/* To determine the best allocation of reds, greens, and blues in a 
 * standard colormap, use XmuGetColormapAllocation.
 * 	vinfo		specifies visual information for a chosen visual
 *	property	specifies one of the standard colormap property names
 * 	red_max		returns maximum red value 
 *      green_max	returns maximum green value
 * 	blue_max	returns maximum blue value
 *
 * XmuGetColormapAllocation returns 0 on failure, non-zero on success.
 * It is assumed that the visual is appropriate for the colormap property.
 */

Status XmuGetColormapAllocation(vinfo, property, red_max, green_max, blue_max)
    XVisualInfo		*vinfo;
    Atom		property;
    unsigned long	*red_max, *green_max, *blue_max;
{
    Status 	status = 1;

    if (vinfo->colormap_size <= 2)
	return 0;

    switch (property)
    {
      case XA_RGB_DEFAULT_MAP:
	status = default_allocation(vinfo, red_max, green_max, blue_max);
	break;
      case XA_RGB_BEST_MAP:
	best_allocation(vinfo, red_max, green_max, blue_max);
	break;
      case XA_RGB_GRAY_MAP:
	gray_allocation(vinfo->colormap_size, red_max, green_max, blue_max);
	break;
      case XA_RGB_RED_MAP:
	*red_max = vinfo->colormap_size - 1;
	*green_max = *blue_max = 0;
	break;
      case XA_RGB_GREEN_MAP:
	*green_max = vinfo->colormap_size - 1;
	*red_max = *blue_max = 0;
	break;
      case XA_RGB_BLUE_MAP:
	*blue_max = vinfo->colormap_size - 1;
	*red_max = *green_max = 0;
	break;
      default:
	status = 0;
    }
    return status;
}

/****************************************************************************/
/* Determine the appropriate color allocations of a gray scale.
 *
 * Keith Packard, MIT X Consortium
 */

static void gray_allocation(n, red_max, green_max, blue_max)
    int		n;	/* the number of cells of the gray scale */
    unsigned long *red_max, *green_max, *blue_max;
{
    *red_max = (n * 30) / 100;
    *green_max = (n * 59) / 100; 
    *blue_max = (n * 11) / 100; 
    *green_max += ((n - 1) - (*red_max + *green_max + *blue_max));
}

/****************************************************************************/
/* Determine an appropriate color allocation for the RGB_DEFAULT_MAP.
 * If a map has less than a minimum number of definable entries, we do not
 * produce an allocation for an RGB_DEFAULT_MAP.  
 *
 * For 16 planes, the default colormap will have 27 each RGB; for 12 planes,
 * 12 each.  For 8 planes, let n = the number of colormap entries, which may
 * be 256 or 254.  Then, maximum red value = floor(cube_root(n - 125)) - 1.
 * Maximum green and maximum blue values are identical to maximum red.
 * This leaves at least 125 cells which clients can allocate.
 *
 * Return 0 if an allocation has been determined, non-zero otherwise.
 */

static int default_allocation(vinfo, red, green, blue)
    XVisualInfo		*vinfo;
    unsigned long	*red, *green, *blue;
{
    int			ngrays;		/* number of gray cells */

    if (vinfo->colormap_size < 250)	/* skip it */
	return 0;

    switch (vinfo->class) {
      case PseudoColor:

	if (vinfo->colormap_size > 65000)
	    /* intended for displays with 16 planes */
	    *red = *green = *blue = (unsigned long) 27;
	else if (vinfo->colormap_size > 4000)
	    /* intended for displays with 12 planes */
	    *red = *green = *blue = (unsigned long) 12;
	else
	    /* intended for displays with 8 planes */
	    *red = *green = *blue = (unsigned long)
		(icbrt(vinfo->colormap_size - 125) - 1);
	break;

      case DirectColor:

	*red = *green = *blue = vinfo->colormap_size / 2 - 1;
	break;

      case TrueColor:

	*red = vinfo->red_mask / lowbit(vinfo->red_mask);
	*green = vinfo->green_mask / lowbit(vinfo->green_mask);
	*blue = vinfo->blue_mask / lowbit(vinfo->blue_mask);
	break;

      case GrayScale:

	if (vinfo->colormap_size > 65000)
	    ngrays = 4096;
	else if (vinfo->colormap_size > 4000)
	    ngrays = 512;
	else
	    ngrays = 12;
	gray_allocation(ngrays, red, green, blue);
	break;
	
      default:
	return 0;
    }
    return 1;
}

/****************************************************************************/
/* Determine an appropriate color allocation for the RGB_BEST_MAP.
 *
 * For a DirectColor or TrueColor visual, the allocation is determined
 * by the red_mask, green_mask, and blue_mask members of the visual info.
 *
 * Otherwise, if the colormap size is an integral power of 2, determine
 * the allocation according to the number of bits given to each color,
 * with green getting more than red, and red more than blue, if there
 * are to be inequities in the distribution.  If the colormap size is
 * not an integral power of 2, let n = the number of colormap entries.
 * Then maximum red value = floor(cube_root(n)) - 1;
 * 	maximum blue value = floor(cube_root(n)) - 1;
 *	maximum green value = n / ((# red values) * (# blue values)) - 1;
 * Which, on a GPX, allows for 252 entries in the best map, out of 254
 * defineable colormap entries.
 */
 
static void best_allocation(vinfo, red, green, blue)
    XVisualInfo		*vinfo;
    unsigned long	*red, *green, *blue;
{

    if (vinfo->class == DirectColor ||	vinfo->class == TrueColor)
    {
	*red = vinfo->red_mask;
	while ((*red & 01) == 0)
	    *red >>= 1;
	*green = vinfo->green_mask;
	while ((*green & 01) == 0)
	    *green >>=1;
	*blue = vinfo->blue_mask;
	while ((*blue & 01) == 0)
	    *blue >>= 1;
    }
    else
    {
	register int bits, n;
	
	/* Determine n such that n is the least integral power of 2 which is
	 * greater than or equal to the number of entries in the colormap.
         */
	n = 1;
	bits = 0;
	while (vinfo->colormap_size > n)
	{
	    n = n << 1;
	    bits++;
	}
	
	/* If the number of entries in the colormap is a power of 2, determine
	 * the allocation by "dealing" the bits, first to green, then red, then
	 * blue.  If not, find the maximum integral red, green, and blue values
	 * which, when multiplied together, do not exceed the number of 

	 * colormap entries.
	 */
	if (n == vinfo->colormap_size)
	{
	    register int r, g, b;
	    b = bits / 3;
	    g = b + ((bits % 3) ? 1 : 0);
	    r = b + (((bits % 3) == 2) ? 1 : 0);
	    *red = 1 << r;
	    *green = 1 << g;
	    *blue = 1 << b;
	}
	else
	{
	    *red = icbrt_with_bits(vinfo->colormap_size, bits);
	    *blue = *red;	
	    *green = (vinfo->colormap_size / ((*red) * (*blue)));
	}
	(*red)--;
	(*green)--;
	(*blue)--;
    }
    return;
}

/*
 * integer cube roots by Newton's method
 *
 * Stephen Gildea, MIT X Consortium, July 1991
 */

static int icbrt(a)		/* integer cube root */
    int a;
{
    register int bits = 0;
    register unsigned n = a;

    while (n)
    {
	bits++;
	n >>= 1;
    }
    return icbrt_with_bits(a, bits);
}


static int icbrt_with_bits(a, bits)
    int a;
    int bits;			/* log 2 of a */
{
    return icbrt_with_guess(a, a>>2*bits/3);
}

#ifdef _X_ROOT_STATS
int icbrt_loopcount;
#endif

/* Newton's Method:  x_n+1 = x_n - ( f(x_n) / f'(x_n) ) */

/* for cube roots, x^3 - a = 0,  x_new = x - 1/3 (x - a/x^2) */

/*
 * Quick and dirty cube roots.  Nothing fancy here, just Newton's method.
 * Only works for positive integers (since that's all we need).
 * We actually return floor(cbrt(a)) because that's what we need here, too.
 */

static int icbrt_with_guess(a, guess)
    int a, guess;
{
    register int delta;

#ifdef _X_ROOT_STATS
    icbrt_loopcount = 0;
#endif
    if (a <= 0)
	return 0;
    if (guess < 1)
	guess = 1;

    do {
#ifdef _X_ROOT_STATS
	icbrt_loopcount++;
#endif
	delta = (guess - a/(guess*guess))/3;
#ifdef DEBUG
	printf("pass %d: guess=%d, delta=%d\n", icbrt_loopcount, guess, delta);
#endif
	guess -= delta;
    } while (delta != 0);

    if (guess*guess*guess > a)
	guess--;

    return guess;
}
